Optimal. Leaf size=82 \[ \frac{1}{2} b^2 x (6 a-5 b)-\frac{(a-b)^3 \tanh ^3(c+d x)}{3 d}+\frac{(a-b)^2 (a+2 b) \tanh (c+d x)}{d}+\frac{b^3 \sinh (c+d x) \cosh (c+d x)}{2 d} \]
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Rubi [A] time = 0.108489, antiderivative size = 82, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {3191, 390, 385, 206} \[ \frac{1}{2} b^2 x (6 a-5 b)-\frac{(a-b)^3 \tanh ^3(c+d x)}{3 d}+\frac{(a-b)^2 (a+2 b) \tanh (c+d x)}{d}+\frac{b^3 \sinh (c+d x) \cosh (c+d x)}{2 d} \]
Antiderivative was successfully verified.
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Rule 3191
Rule 390
Rule 385
Rule 206
Rubi steps
\begin{align*} \int \text{sech}^4(c+d x) \left (a+b \sinh ^2(c+d x)\right )^3 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a-(a-b) x^2\right )^3}{\left (1-x^2\right )^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left ((a-b)^2 (a+2 b)-(a-b)^3 x^2+\frac{(3 a-2 b) b^2-3 (a-b) b^2 x^2}{\left (1-x^2\right )^2}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{(a-b)^2 (a+2 b) \tanh (c+d x)}{d}-\frac{(a-b)^3 \tanh ^3(c+d x)}{3 d}+\frac{\operatorname{Subst}\left (\int \frac{(3 a-2 b) b^2-3 (a-b) b^2 x^2}{\left (1-x^2\right )^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{b^3 \cosh (c+d x) \sinh (c+d x)}{2 d}+\frac{(a-b)^2 (a+2 b) \tanh (c+d x)}{d}-\frac{(a-b)^3 \tanh ^3(c+d x)}{3 d}+\frac{\left ((6 a-5 b) b^2\right ) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\tanh (c+d x)\right )}{2 d}\\ &=\frac{1}{2} (6 a-5 b) b^2 x+\frac{b^3 \cosh (c+d x) \sinh (c+d x)}{2 d}+\frac{(a-b)^2 (a+2 b) \tanh (c+d x)}{d}-\frac{(a-b)^3 \tanh ^3(c+d x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.738259, size = 84, normalized size = 1.02 \[ \frac{6 b^2 (6 a-5 b) (c+d x)+2 (a-b)^2 \tanh (c+d x) \text{sech}^2(c+d x) ((2 a+7 b) \cosh (2 (c+d x))+4 a+5 b)+3 b^3 \sinh (2 (c+d x))}{12 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.054, size = 148, normalized size = 1.8 \begin{align*}{\frac{1}{d} \left ({a}^{3} \left ({\frac{2}{3}}+{\frac{ \left ({\rm sech} \left (dx+c\right ) \right ) ^{2}}{3}} \right ) \tanh \left ( dx+c \right ) +3\,{a}^{2}b \left ( -1/2\,{\frac{\sinh \left ( dx+c \right ) }{ \left ( \cosh \left ( dx+c \right ) \right ) ^{3}}}+1/2\, \left ( 2/3+1/3\, \left ({\rm sech} \left (dx+c\right ) \right ) ^{2} \right ) \tanh \left ( dx+c \right ) \right ) +3\,a{b}^{2} \left ( dx+c-\tanh \left ( dx+c \right ) -1/3\, \left ( \tanh \left ( dx+c \right ) \right ) ^{3} \right ) +{b}^{3} \left ({\frac{ \left ( \sinh \left ( dx+c \right ) \right ) ^{5}}{2\, \left ( \cosh \left ( dx+c \right ) \right ) ^{3}}}-{\frac{5\,dx}{2}}-{\frac{5\,c}{2}}+{\frac{5\,\tanh \left ( dx+c \right ) }{2}}+{\frac{5\, \left ( \tanh \left ( dx+c \right ) \right ) ^{3}}{6}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.14396, size = 516, normalized size = 6.29 \begin{align*} a b^{2}{\left (3 \, x + \frac{3 \, c}{d} - \frac{4 \,{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + 2\right )}}{d{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} - \frac{1}{24} \, b^{3}{\left (\frac{60 \,{\left (d x + c\right )}}{d} + \frac{3 \, e^{\left (-2 \, d x - 2 \, c\right )}}{d} - \frac{121 \, e^{\left (-2 \, d x - 2 \, c\right )} + 201 \, e^{\left (-4 \, d x - 4 \, c\right )} + 147 \, e^{\left (-6 \, d x - 6 \, c\right )} + 3}{d{\left (e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + 3 \, e^{\left (-6 \, d x - 6 \, c\right )} + e^{\left (-8 \, d x - 8 \, c\right )}\right )}}\right )} + \frac{4}{3} \, a^{3}{\left (\frac{3 \, e^{\left (-2 \, d x - 2 \, c\right )}}{d{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}} + \frac{1}{d{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} + 2 \, a^{2} b{\left (\frac{3 \, e^{\left (-4 \, d x - 4 \, c\right )}}{d{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}} + \frac{1}{d{\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.5977, size = 788, normalized size = 9.61 \begin{align*} \frac{3 \, b^{3} \sinh \left (d x + c\right )^{5} - 4 \,{\left (4 \, a^{3} + 6 \, a^{2} b - 24 \, a b^{2} + 14 \, b^{3} - 3 \,{\left (6 \, a b^{2} - 5 \, b^{3}\right )} d x\right )} \cosh \left (d x + c\right )^{3} - 12 \,{\left (4 \, a^{3} + 6 \, a^{2} b - 24 \, a b^{2} + 14 \, b^{3} - 3 \,{\left (6 \, a b^{2} - 5 \, b^{3}\right )} d x\right )} \cosh \left (d x + c\right ) \sinh \left (d x + c\right )^{2} +{\left (30 \, b^{3} \cosh \left (d x + c\right )^{2} + 16 \, a^{3} + 24 \, a^{2} b - 96 \, a b^{2} + 65 \, b^{3}\right )} \sinh \left (d x + c\right )^{3} - 12 \,{\left (4 \, a^{3} + 6 \, a^{2} b - 24 \, a b^{2} + 14 \, b^{3} - 3 \,{\left (6 \, a b^{2} - 5 \, b^{3}\right )} d x\right )} \cosh \left (d x + c\right ) + 3 \,{\left (5 \, b^{3} \cosh \left (d x + c\right )^{4} + 16 \, a^{3} - 24 \, a^{2} b + 10 \, b^{3} +{\left (16 \, a^{3} + 24 \, a^{2} b - 96 \, a b^{2} + 65 \, b^{3}\right )} \cosh \left (d x + c\right )^{2}\right )} \sinh \left (d x + c\right )}{24 \,{\left (d \cosh \left (d x + c\right )^{3} + 3 \, d \cosh \left (d x + c\right ) \sinh \left (d x + c\right )^{2} + 3 \, d \cosh \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.37152, size = 290, normalized size = 3.54 \begin{align*} \frac{b^{3} e^{\left (2 \, d x + 2 \, c\right )}}{8 \, d} + \frac{{\left (6 \, a b^{2} - 5 \, b^{3}\right )}{\left (d x + c\right )}}{2 \, d} - \frac{{\left (12 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )} - 10 \, b^{3} e^{\left (2 \, d x + 2 \, c\right )} + b^{3}\right )} e^{\left (-2 \, d x - 2 \, c\right )}}{8 \, d} - \frac{2 \,{\left (9 \, a^{2} b e^{\left (4 \, d x + 4 \, c\right )} - 18 \, a b^{2} e^{\left (4 \, d x + 4 \, c\right )} + 9 \, b^{3} e^{\left (4 \, d x + 4 \, c\right )} + 6 \, a^{3} e^{\left (2 \, d x + 2 \, c\right )} - 18 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )} + 12 \, b^{3} e^{\left (2 \, d x + 2 \, c\right )} + 2 \, a^{3} + 3 \, a^{2} b - 12 \, a b^{2} + 7 \, b^{3}\right )}}{3 \, d{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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